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Mar 6, 2011 at 10:44 comment added Guillermo Mantilla @aglearner: my mind sometimes pictures $\mathbb{C}^2$ as a "real" plane. Good catch.
Mar 6, 2011 at 10:11 comment added aglearner Guillermo thnaks. Just a nitpick, $\mathbb A^2(\mathbb C)-0$ is simply connected, you need to use $\pi_3(Y)=\mathbb Z$.
Mar 6, 2011 at 4:42 history answered Guillermo Mantilla CC BY-SA 2.5