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Jan 3 at 15:23 comment added Joel David Hamkins @DanielDonnelly By operation I simply mean a binary function on the integers $(m,n)\mapsto m\star n$, which takes two integer inputs $m$ and $n$ and has value $m\star n$. The question is not about run-time or computational complexity, but rather about the whether there is such an operation $\star$ for which $m+n$ and $m\cdot n$ can both be expressed entirely as terms using $\star$ only.
Jan 3 at 2:11 comment added Daniel Donnelly You haven't correctly identified what is allowed as an "operation". For example, you implicitly assume we all consider $\text{id}(x)$ to be a non-operation. But on the other hand $-x$ which is usually considered unary. Otoh, if you have identified all $-x$ in some finite group say, then that operation is similarly only $O(1)$ in run time as $\text{id}(x)$ which we'll call memory look up. So I will only answer if you lay out some rules, otherwise I'm voting to close as clearly too broad.
Apr 13, 2017 at 12:19 history edited CommunityBot
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Sep 23, 2014 at 3:42 answer added user44143 timeline score: 5
May 13, 2011 at 17:37 vote accept Joel David Hamkins
May 13, 2011 at 16:14 answer added Someone timeline score: 4
May 12, 2011 at 17:02 answer added Goldstern timeline score: 33
Mar 5, 2011 at 20:25 answer added Gerhard Paseman timeline score: 6
Mar 5, 2011 at 20:13 answer added Terry Tao timeline score: 18
Mar 5, 2011 at 19:55 answer added Andrej Bauer timeline score: 16
Mar 5, 2011 at 19:14 answer added Terry Tao timeline score: 39
Mar 5, 2011 at 18:56 comment added Joel David Hamkins Asaf, indeed, one can easily define the operations by formulas of first order logic as in your exercise. In my question, however, I am seeking a binary operation having mere terms that give rise to the given functions.
Mar 5, 2011 at 18:43 comment added Gerhard Paseman There is a notion of universal term. When I get to my copy of ALV, I will look it up. I remember it as an exercise as well as work done by George McNulty. Gerhard "Ask Me About Clone Theory" Paseman, 2011.03.05
Mar 5, 2011 at 18:20 answer added Gerald Edgar timeline score: 1
Mar 5, 2011 at 18:18 comment added José Figueroa-O'Farrill Although most probably unrelated to your question, something of this ilk happens in the context of Poisson algebras. In a Poisson algebra there are two operations: a commutative, associative multiplication and a Lie bracket, subject to a compatibility condition. It is possible to unify them into one product whose symmetric part is the commutative multiplication and the antisymmetric part is the Lie bracket.
Mar 5, 2011 at 18:11 answer added Guntram timeline score: 0
Mar 5, 2011 at 16:46 comment added Asaf Karagila In the introductory course I was TA'ing last semester we gave an exercise to define $\le$, $+$ and $\cdot$ from $a\mod b$ (when everything is zero when taken mod 0).
Mar 5, 2011 at 16:09 comment added M.G. Very interesting question! (By some coincidence I was wondering about a similar thing myself too...)
Mar 5, 2011 at 15:35 history asked Joel David Hamkins CC BY-SA 2.5