Timeline for Why isn't the orbifold cohomology of $pt/G$ equal to the cohomology of $BG$?
Current License: CC BY-SA 2.5
3 events
| when toggle format | what | by | license | comment | |
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| Mar 24, 2011 at 19:12 | vote | accept | Simon Rose | ||
| Mar 3, 2011 at 2:54 | comment | added | David Roberts♦ | ...where $G/G$ is the quotient by the adjoint action of $G$ on itself, in case it wasn't clear. | |
| Mar 3, 2011 at 1:20 | history | answered | David Ben-Zvi | CC BY-SA 2.5 |