Timeline for Five points in spheres
Current License: CC BY-SA 2.5
12 events
| when toggle format | what | by | license | comment | |
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| Mar 9, 2011 at 22:51 | comment | added | Fedor Petrov | As for the second question, the answer is also positive, proved by Hiroshi Maeharaa and Norihide Tokushigea, in European Journal of Combinatorics (Volume 30, Issue 5, July 2009, Pages 1337-1351). | |
| Mar 4, 2011 at 19:26 | comment | added | Fedor Petrov | sorry, this is false. Such construction is impossible. | |
| Mar 2, 2011 at 21:51 | comment | added | ε-δ | Note that vertices of triangle plus orthocenter give a solution of the analog problem in 2D. | |
| Mar 2, 2011 at 19:41 | answer | added | Mark Bennet | timeline score: 0 | |
| Mar 2, 2011 at 18:16 | history | edited | Kevin O'Bryant | CC BY-SA 2.5 |
interpreted question in two (both interesting) ways
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| Mar 2, 2011 at 16:44 | answer | added | Fedor Petrov | timeline score: 17 | |
| Mar 2, 2011 at 15:49 | comment | added | Qfwfq | Some background/motivation? | |
| Mar 2, 2011 at 15:43 | comment | added | Peter Shor | The OP is looking for a set of five points so that, for every four of them, the four points are contained in a ball (or maybe on a sphere) of radius 1, and yet all five are not. I think we have a foreign-language issue here, in that the English is not precise enough to tell whether he is asking for "on the surface of a sphere" or "in the interior of a ball". | |
| Mar 2, 2011 at 15:31 | comment | added | aaron | The question seems to be: do there exist 5 points in $R^3$ with ... [a certain property]? | |
| Mar 2, 2011 at 15:04 | comment | added | ARupinski | What exactly is the question? | |
| Mar 2, 2011 at 14:52 | comment | added | aaron | When you say "in a sphere" do you mean "on a sphere"? | |
| Mar 2, 2011 at 14:31 | history | asked | José Araujo | CC BY-SA 2.5 |