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Timeline for Special Killing Vector Fields

Current License: CC BY-SA 2.5

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Mar 2, 2011 at 20:44 vote accept Rbega
Mar 2, 2011 at 20:38 answer added José Figueroa-O'Farrill timeline score: 2
Mar 2, 2011 at 18:03 answer added agt timeline score: 2
Mar 2, 2011 at 13:00 comment added José Figueroa-O'Farrill Not a complete answer, but such Killing vectors are twist-free; although this condition seems stronger. Recall that a Killing vector $X$ is twist-free if $X^\flat \wedge dX^\flat = 0$, where $X^\flat = g(X,\cdot)$ in your notation.
Mar 2, 2011 at 5:52 history asked Rbega CC BY-SA 2.5