Timeline for Must a linearly ordered, separable space be metrizable?
Current License: CC BY-SA 2.5
11 events
| when toggle format | what | by | license | comment | |
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| May 25, 2018 at 10:09 | comment | added | Henno Brandsma | Yes, if $X$ is connected, then $X$ has no jumps (points $x < y$ with no points inbetween), and then $d(X) = w(X)$. Urysohn does the rest. | |
| Mar 1, 2011 at 20:29 | comment | added | Peter Arndt | Not an answer but a fun comment: Here is a simple criterion of when trees are metriable: google.com/… | |
| Mar 1, 2011 at 19:03 | vote | accept | mathahada | ||
| Mar 1, 2011 at 18:39 | answer | added | Henno Brandsma | timeline score: 8 | |
| Mar 1, 2011 at 14:37 | answer | added | Michael Greinecker | timeline score: 1 | |
| Mar 1, 2011 at 11:26 | vote | accept | mathahada | ||
| Mar 1, 2011 at 19:03 | |||||
| Mar 1, 2011 at 9:20 | history | edited | mathahada | CC BY-SA 2.5 |
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| Mar 1, 2011 at 0:47 | answer | added | Jim Conant | timeline score: 1 | |
| Mar 1, 2011 at 0:09 | history | edited | mathahada | CC BY-SA 2.5 |
added 438 characters in body; added 98 characters in body
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| Mar 1, 2011 at 0:01 | answer | added | Apollo | timeline score: 4 | |
| Feb 28, 2011 at 23:53 | history | asked | mathahada | CC BY-SA 2.5 |