Timeline for Upper bound on the area of a midpoint pentagon?
Current License: CC BY-SA 2.5
12 events
when toggle format | what | by | license | comment | |
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Nov 19, 2009 at 21:35 | comment | added | Kristal Cantwell | I finally got this to work and got the difference between 3/4 of the area of the original polygon and the area of the midpoint polygon as an expression of geometrical figures in the original polygon everything before this didn't work because I was trying to get too big a difference between areas. | |
Nov 19, 2009 at 21:25 | history | edited | Kristal Cantwell | CC BY-SA 2.5 |
major rewrite
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Nov 18, 2009 at 2:45 | history | edited | Kristal Cantwell | CC BY-SA 2.5 |
I have redone the proof.
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Nov 17, 2009 at 1:17 | comment | added | Kristal Cantwell | I think I see the problem with what I did. The triangle NDE appears with another term in Speyer's proof. I think that term corresponds to triangle MBN. I think I could eventually get a geometric equivalent to the difference between the 3/4 area and the area of the half point pentagon but there is a complication that it involves the area of two triangles at least one of which may have to be subtracted in some cases. | |
Nov 16, 2009 at 20:33 | history | edited | Kristal Cantwell | CC BY-SA 2.5 |
addition of material
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Nov 16, 2009 at 19:40 | history | edited | Kristal Cantwell | CC BY-SA 2.5 |
added material
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Nov 16, 2009 at 19:01 | comment | added | Kristal Cantwell | There were mistakes I think I have fixed them. | |
Nov 16, 2009 at 19:01 | history | edited | Kristal Cantwell | CC BY-SA 2.5 |
major changes
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Nov 16, 2009 at 3:51 | comment | added | Hugh Thomas | Holding three corners of the pentagon fixed and multiplying the other two by a large constant, the area of the middle pentagon should tend towards 1/2 -- the pentagon is almost a triangle, two quarters of which are filled by the middle pentagon. I'm also worried about your calculation of the area of the original pentagon -- it seems to me that it need not be more than 1/2 the determinant of (x_1,y_1) and (x_2,y_2): for example, if (x_1,y_1) is close to the x-axis and (x_2,y_2) is close to the y axis. | |
Nov 16, 2009 at 3:41 | history | edited | Kristal Cantwell | CC BY-SA 2.5 |
minor changes
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Nov 16, 2009 at 3:34 | history | edited | Kristal Cantwell | CC BY-SA 2.5 |
spelling correction
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Nov 16, 2009 at 3:22 | history | answered | Kristal Cantwell | CC BY-SA 2.5 |