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Feb 26, 2011 at 20:58 comment added yurius Of course, if $V$ is a Hilbert space, then Hellinger-Toeplitz applies
Feb 26, 2011 at 20:57 comment added yurius yes, I mean inner-product space
Feb 25, 2011 at 20:31 comment added Matthew Daws Does "unitary space" you mean "inner-product space" (i.e. differs from a Hilbert space by being not complete)?
Feb 25, 2011 at 20:08 comment added András Bátkai Ups, I made a mistake, of course the product will be selfadjoint, even in the unbounded case. Sorry, sorry. So now I am really lost... Maybe I am a bit slow.
Feb 25, 2011 at 19:55 comment added András Bátkai I have to confess that I do not completely understand your question. An oprator $A:V\to V$, which is positive, has to be bounded by Hellinger-Toeplitz. If $A$ and $B$ are not everywhere defined, unbounded commuting selfadjoint operators, then the product is still positive, but not necessarily selfadjoint. Is this your question?
Feb 25, 2011 at 15:07 history asked yurius CC BY-SA 2.5