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Feb 26, 2011 at 11:44 vote accept Tommaso Centeleghe
Feb 25, 2011 at 11:58 history edited François Brunault CC BY-SA 2.5
Corrected spelling
Feb 25, 2011 at 10:36 comment added Tommaso Centeleghe This is precisely the way I was trying to prove the statement yesterday, as I was talking to a friend. In the chain of isomorphisms you describe above, probably it is not so essential that $\mathbf{Z}[\alpha]=\mathcal{O}_K$, I will check if the same argument works when $\mathbf{Z}[\alpha]$ is not even finite over $\mathbf{Z}$, i.e. when $\alpha$ is not an algebraic integer. Thanks!!
Feb 25, 2011 at 1:46 history edited François Brunault CC BY-SA 2.5
Trying to parse the LaTeX code
Feb 25, 2011 at 1:39 history answered François Brunault CC BY-SA 2.5