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Here is a way of generating lots of examples:

Start with a variety $X$ with an effective cone which is not rational polyhedral (i.e., not finitely generated) and let $L_1,\ldots,L_r$ be a collection of line bundles on $X$ such that their positive span $\{L_1^{a_1}\otimes \cdots\otimes L_r^{a_r} | a_1,\ldots,a_r \ge 0\}$ includes the effective cone. For example, one could take $X$ to be the blow-up of projective space at sufficiently many points, or a K3 surface of maximal Picard number.

Now consider the variety $Y=\mathbb{P}(E)$ where $E=L_1\oplus \cdots \oplus L_r$ and the line bundle $O(1)$ on $Y$. We have for $n\ge\0$, $$ H^0(Y,O(n))\cong H^0(X,Sym^n(E))=\bigoplus_{a_1+\ldots +a_r=n}H^0(X,L_1^{a_1}\otimes \cdots\otimes L_r^{a_r}) $$so that $R(Y,O(1))$ is isomorphic to the sum of all sections of all effective line bundles on $X$: this is usually called the Cox ring of $X$. When the effective cone of $X$ is non-rational polyhedral it is clear that this ring is infinitely generated, since it requires sections from all effective divisor classes.

It is usually a difficult problem in birational geometry to decide when a nef and big divisor is semiample, i.e., some multiple of $D$ is base-point free. A well-known theorem of Zariski says that if $X$ is normal and projective, then $D$ is semiample if and only if the section ring $R(X,D)$ is finitely generated. So this theorem gives a way of producing nef and big divisors which are not semiample. In particular, choosing $X$ such that the nef-big cone is not rational polyhedral, $L=O(1)$ is nef and big, but not semiample, since $R(Y,L)$ is not finitely generated.

Here is a way of generating lots of examples:

Start with a variety $X$ with an effective cone which is not rational polyhedral (i.e., not finitely generated) and let $L_1,\ldots,L_r$ be a collection of line bundles on $X$ such that their span $\{L_1^{a_1}\otimes \cdots\otimes L_r^{a_r} | a_1,\ldots,a_r \ge 0\}\,\,$ includes the effective cone. For example, one could take $X$ to be the blow-up of projective space at sufficiently many points, or a K3 surface of maximal Picard number.

Now consider the variety $Y=\mathbb{P}(E)$ where $E=L_1\oplus \cdots \oplus L_r$ and the line bundle $O(1)$ on $Y$. We have for $n\geq 0$, $$ H^0(Y,O(n))\cong H^0(X,Sym^n(E))=\bigoplus_{a_1+\ldots +a_r=n}H^0(X,L_1^{a_1}\otimes \cdots\otimes L_r^{a_r}) $$so that $R(Y,O(1))$ is isomorphic to the sum of all sections of all effective line bundles on $X$: this is usually called the Cox ring of $X$. When the effective cone of $X$ is non-rational polyhedral it is clear that this ring is infinitely generated, since it requires sections from all effective divisor classes.

It is usually a difficult problem in birational geometry to decide when a nef and big divisor is semiample, i.e., some multiple of $D$ is base-point free. A well-known theorem of Zariski says that if $X$ is normal and projective, then $D$ is semiample if and only if the section ring $R(X,D)$ is finitely generated. So this theorem gives a way of producing nef and big divisors which are not semiample. In particular, choosing $X$ such that the nef-big cone is not rational polyhedral, $L=O(1)$ is nef and big, but not semiample, since $R(Y,L)$ is not finitely generated.

Here is a way of generating lots of examples:

Start with a variety $X$ with an effective cone which is not rational polyhedral (i.e., not finitely generated) and let $L_1,\ldots,L_r$ be line bundles forming a basis for $Pic(X)$. For example, one could take $X$ to be the blow-up of projective space at sufficiently many points, or a K3 surface of maximal Picard number.

Now consider the variety $Y=\mathbb{P}(E)$ where $E=L_1\oplus \cdots \oplus L_r$ and the line bundle $O(1)$ on $Y$. We have for $n\ge\0$, $$ H^0(Y,O(n))\cong H^0(X,Sym^n(E))=\bigoplus_{a_1+\ldots +a_r=n}H^0(X,L_1^{a_1}\otimes \cdots\otimes L_r^{a_r}) $$so that $R(Y,O(1))$ is isomorphic to the sum of all sections of all effective line bundles on $X$: this is usually called the Cox ring of $X$. When the effective cone of $X$ is non-rational polyhedral it is clear that this ring is infinitely generated, since it requires sections from all effective divisor classes.

It is usually a difficult problem in birational geometry to decide when a nef and big divisor is semiample, i.e., some multiple of $D$ is base-point free. A well-known theorem of Zariski says that if $X$ is normal and projective, then $D$ is semiample if and only if the section ring $R(X,D)$ is finitely generated. So this theorem gives a way of producing nef and big divisors which are not semiample. In particular, choosing $X$ such that the nef-big cone is not rational polyhedral, $L=O(1)$ is nef and big, but not semiample, since $R(Y,L)$ is not finitely generated.

Here is a way of generating lots of examples:

Start with a variety $X$ with an effective cone which is not rational polyhedral (i.e., not finitely generated) and let $L_1,\ldots,L_r$ be a collection of line bundles on $X$ such that their positive span $\{L_1^{a_1}\otimes \cdots\otimes L_r^{a_r} | a_1,\ldots,a_r \ge 0\}$ includes the effective cone. For example, one could take $X$ to be the blow-up of projective space at sufficiently many points, or a K3 surface of maximal Picard number.

Now consider the variety $Y=\mathbb{P}(E)$ where $E=L_1\oplus \cdots \oplus L_r$ and the line bundle $O(1)$ on $Y$. We have for $n\ge\0$, $$ H^0(Y,O(n))\cong H^0(X,Sym^n(E))=\bigoplus_{a_1+\ldots +a_r=n}H^0(X,L_1^{a_1}\otimes \cdots\otimes L_r^{a_r}) $$so that $R(Y,O(1))$ is isomorphic to the sum of all sections of all effective line bundles on $X$: this is usually called the Cox ring of $X$. When the effective cone of $X$ is non-rational polyhedral it is clear that this ring is infinitely generated, since it requires sections from all effective divisor classes.

It is usually a difficult problem in birational geometry to decide when a nef and big divisor is semiample, i.e., some multiple of $D$ is base-point free. A well-known theorem of Zariski says that if $X$ is normal and projective, then $D$ is semiample if and only if the section ring $R(X,D)$ is finitely generated. So this theorem gives a way of producing nef and big divisors which are not semiample. In particular, choosing $X$ such that the nef-big cone is not rational polyhedral, $L=O(1)$ is nef and big, but not semiample, since $R(Y,L)$ is not finitely generated.

Here is a way of generating lots of examples:

Start with a variety $X$ with an effective cone which is not rational polyhedral (i.e., not finitely generated) and let $L_1,\ldots,L_r$ be line bundles forming a basis for $Pic(X)$. For example, one could take $X$ to be the blow-up of projective space at sufficiently many points, or a K3 surface of maximal Picard number.

Now consider the variety $Y=\mathbb{P}(E)$ where $E=L_1\oplus \cdots \oplus L_r$ and the line bundle $O(1)$ on $Y$. We have for $n\ge\0$, $$ H^0(Y,O(n))\cong H^0(X,Sym^n(E))=\bigoplus_{a_1+\ldots +a_r=n}H^0(X,L_1^{a_1}\otimes L_r^{a_r}) $$so that $R(Y,O(1))$ is isomorphic to the sum of all sections of all line bundles on $X$: the Cox ring of $X$. When the effective cone of $X$ is non-rational polyhedral it is clear that this ring is infinitely generated, since it requires sections from all effective divisor classes.

It is usually a difficult problem in birational geometry to decide when a nef and big divisor is semiample, i.e., some multiple of $D$ is base-point free. A well-known theorem of Zariski says that if $X$ is normal and projective, then $D$ is semiample if and only if the section ring $R(X,D)$ is finitely generated. So this theorem gives a way of producing nef and big divisors which are not semiample. In particular, choosing $X$ such that the nef-big cone is not rational polyhedral, $L=O(1)$ is nef and big, but not semiample, since $R(Y,L)$ is not finitely generated.

Here is a way of generating lots of examples:

Start with a variety $X$ with an effective cone which is not rational polyhedral (i.e., not finitely generated) and let $L_1,\ldots,L_r$ be line bundles forming a basis for $Pic(X)$. For example, one could take $X$ to be the blow-up of projective space at sufficiently many points, or a K3 surface of maximal Picard number.

Now consider the variety $Y=\mathbb{P}(E)$ where $E=L_1\oplus \cdots \oplus L_r$ and the line bundle $O(1)$ on $Y$. We have for $n\ge\0$, $$ H^0(Y,O(n))\cong H^0(X,Sym^n(E))=\bigoplus_{a_1+\ldots +a_r=n}H^0(X,L_1^{a_1}\otimes \cdots\otimes L_r^{a_r}) $$so that $R(Y,O(1))$ is isomorphic to the sum of all sections of all effective line bundles on $X$: this is usually called the Cox ring of $X$. When the effective cone of $X$ is non-rational polyhedral it is clear that this ring is infinitely generated, since it requires sections from all effective divisor classes.

It is usually a difficult problem in birational geometry to decide when a nef and big divisor is semiample, i.e., some multiple of $D$ is base-point free. A well-known theorem of Zariski says that if $X$ is normal and projective, then $D$ is semiample if and only if the section ring $R(X,D)$ is finitely generated. So this theorem gives a way of producing nef and big divisors which are not semiample. In particular, choosing $X$ such that the nef-big cone is not rational polyhedral, $L=O(1)$ is nef and big, but not semiample, since $R(Y,L)$ is not finitely generated.