Timeline for Factorizing polynomials in $\mathbf{Z}[[x]]$
Current License: CC BY-SA 2.5
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 22, 2011 at 19:44 | comment | added | Pace Nielsen | The problem with 2x-2 is it is not irreducible (you can factor a 2). | |
| Feb 22, 2011 at 19:32 | comment | added | Jizhan Hong | Tommaso: $f(x)=2x-2$ seems to have the same problem? | |
| Feb 22, 2011 at 14:27 | comment | added | Tommaso Centeleghe | Probably it would then be more correct to ask to the equality above expressing the factorization to hold up to units. | |
| Feb 22, 2011 at 14:19 | comment | added | Tommaso Centeleghe | Good point. However in this special case f(x) is a unit in $\mathbf{Z}[[x]]$ and, up to units, the empty product, being equal to 1, is also a unit. | |
| Feb 22, 2011 at 11:53 | history | answered | Laurent Moret-Bailly | CC BY-SA 2.5 |