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Feb 22, 2011 at 4:18 vote accept HNuer
Feb 21, 2011 at 21:55 comment added diverietti Of course this is another possibility. The point is that this is a more general property of Fano manifolds... Of course all this needs $X$ to be smooth...
Feb 21, 2011 at 20:36 comment added HNuer Here's the argument I was thinking of which uses Lefschetz, which I should seen immediately: By Lefschetz $H^{p,q}(\mathbb P^5)$ is isomorphic to $H^{p,q}(C)$ for $p+q<4$, where $C$ is the cubic hypersurface. Applying this again by cutting with the quadric $Q$ to get our $X$, we see that $H^{p,q}(X)$ is isomorphic to $H^{p,q}(C)$ for $p+q<3$. Since the $h^{p,q}(\mathbb P^n)=0$ for $p\neq q$, this gives our result. I suppose since one proves Lefschetz with Kodaira vanishing, it's all the same really, but this is what I had in mind originally.
Feb 21, 2011 at 18:30 answer added diverietti timeline score: 5
Feb 21, 2011 at 18:09 answer added Johannes Nordström timeline score: 8
Feb 21, 2011 at 16:30 history asked HNuer CC BY-SA 2.5