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Sep 15, 2022 at 17:00 history edited Glorfindel CC BY-SA 4.0
broken link fixed, cf. https://meta.mathoverflow.net/q/5301/70594
Jan 25, 2016 at 7:11 answer added Mikhail Ostrovskii timeline score: 1
Jan 26, 2014 at 23:14 history edited user9072
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Jan 26, 2014 at 22:38 history edited Pietro Majer CC BY-SA 3.0
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Feb 22, 2011 at 14:55 comment added Bill Johnson I should mention that the $\sigma$-convex hull of a set came up naturally in the classification of Banach spaces that have the Radon-Nikodym property through Maynard's concept of $s$-dentability. Later Davis and Phelps showed that you could use just dentability, so these days no one talks about $s$-dentability. Their paper jstor.org/pss/2040618 gives the history, including the work of Rieffel that started this line of investigation. Or see the book Vector Measures by Diestel and Uhl.
Feb 22, 2011 at 12:17 history edited Pietro Majer CC BY-SA 2.5
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Feb 22, 2011 at 12:06 comment added Pietro Majer @Bill: actually your example suggests a simple counterexample to my naive conjecture (bounded, convex, and Baire => $\sigma$-convex), in form of a convex subset $C$, $B\subset C\subset \bar B$ between an open, non-strictly convex ball, and its closure. Such a set $C$ is certainly Baire, but it may fail to be $\sigma$-convex, if one face of its is not.
Feb 22, 2011 at 11:37 history edited Pietro Majer CC BY-SA 2.5
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Feb 22, 2011 at 7:29 history edited Pietro Majer CC BY-SA 2.5
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Feb 22, 2011 at 7:28 comment added Pietro Majer Good point. I've added a remark, just to explain why I become interested in the subject.
Feb 22, 2011 at 7:21 history edited Pietro Majer CC BY-SA 2.5
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Feb 21, 2011 at 22:22 comment added Bill Johnson Notice that any subset of the closed unit ball of a Hilbert space (or any strictly convex Banach space) that contains the open unit ball is $\sigma$-absolutely convex, so $\sigma$-absolutely convex sets can be complicated topologically.
Feb 21, 2011 at 22:16 comment added Bill Johnson @Andrew: You are describing the $\sigma$-absolutely convex sets. @Pietro Majer: Continuing what Andrew started, IMO the $\sigma$-convex sets are best described as the image of the positive part of the unit ball of an $\ell_1$ space.
Feb 21, 2011 at 10:50 comment added Andrew Stacey I'm leaving this as a comment as you ask for a topological characterisation. I don't know one, but I do know an algebraic characterisation. What you describe are totally convex spaces as described at ncatlab.org/nlab/show/totally+convex+space in particular, any such set is the image of a unit ball under a continuous map from a Banach space (indeed, an $\ell^1$-space).
Feb 21, 2011 at 10:19 history asked Pietro Majer CC BY-SA 2.5