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Mar 1, 2011 at 14:00 comment added Andreas Thom You are right, I noticed this as well. Anyhow, this does not seem to be a strong inequality.
Mar 1, 2011 at 13:11 comment added Łukasz Grabowski Your proof shows also that $1$ on the right-hand side can be replaced by $|f|_1/|f|$, where $|f|_1$ is the $l^1$-norm of $f$ and $|f|$ is the operator norm of $f$. Which can be interpreted as saying that non-amenable groups are more "Heisenberg-uncertain" than ameanable groups :-).
Feb 21, 2011 at 7:54 history edited Andreas Thom CC BY-SA 2.5
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Feb 20, 2011 at 18:44 vote accept Klim Efremenko
Feb 20, 2011 at 17:36 history edited Andreas Thom CC BY-SA 2.5
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Feb 20, 2011 at 17:22 history answered Andreas Thom CC BY-SA 2.5