Timeline for Geometric interpretation of $BN$-pairs
Current License: CC BY-SA 2.5
12 events
| when toggle format | what | by | license | comment | |
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| Jun 27, 2011 at 20:46 | comment | added | paul garrett | That condition (B), whether copied accurately or not, is troubling. For example, in GL(3,k) over a field k, the largest (spherical) Bruhat cell $Bw_oB$ (with longest Weyl element $w_o$) is such that $Bw_oB\cdot Bw_oB=GL(3,k)$. That is, all 3! of the Bruhat cells are hit. The condition (B) above would require that $Bw_oB\cdot Bw_oB=B\cup Bw_oB$. As Ben W. noted above, it seems likely that $h$ in (B) should be among the $x_i$'s. | |
| Apr 19, 2011 at 16:00 | history | edited | Thomas Connor |
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| Apr 10, 2011 at 13:30 | history | edited | Thomas Connor |
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| Feb 21, 2011 at 8:29 | vote | accept | Thomas Connor | ||
| Feb 21, 2011 at 8:29 | vote | accept | Thomas Connor | ||
| Feb 21, 2011 at 8:29 | |||||
| Feb 20, 2011 at 20:04 | answer | added | Jim Humphreys | timeline score: 9 | |
| Feb 20, 2011 at 18:08 | vote | accept | Thomas Connor | ||
| Feb 21, 2011 at 8:29 | |||||
| Feb 20, 2011 at 18:05 | answer | added | Ben Webster♦ | timeline score: 15 | |
| Feb 20, 2011 at 17:46 | comment | added | Ben Webster♦ | Fair enough. That definition is stronger than the usual definition of B,N-pair (en.wikipedia.org/wiki/(B,_N)_pair) and rules out many interesting examples. | |
| Feb 20, 2011 at 17:31 | comment | added | Thomas Connor | @Ben Webster: I checked again, and I made no mistake in copying it down. | |
| Feb 20, 2011 at 17:11 | comment | added | Ben Webster♦ | I think you must have copied down (B) wrong, since none of the things that are supposed to be examples satisy it. Probably you want $h$ to be one of the $x_i$'s. | |
| Feb 20, 2011 at 17:00 | history | asked | Thomas Connor | CC BY-SA 2.5 |