Timeline for What is the exterior derivative intuitively?
Current License: CC BY-SA 3.0
6 events
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| Jun 9, 2020 at 18:29 | comment | added | Kostya_I | In fact, property 3 already characterizes the exterior derivative uniquely (up to a scalar multiple), see "Natural operations on differential forms" by Palais. | |
| Sep 5, 2017 at 14:19 | comment | added | David E Speyer | I teach this (among other answers) and I also like to assign as a challenge that, if we just ask for a map $d : \Omega^1 \to (\Omega^1)^{\otimes 2}$ obeying (1)-(3), then it is forced to land in the alternating tensors. (Presumably, a similar argument applies for any $p$, but $p=1$ seems hard enough for the students.) | |
| Feb 21, 2013 at 8:53 | history | edited | Johannes Ebert | CC BY-SA 3.0 |
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| Sep 14, 2012 at 21:05 | comment | added | Vectornaut | This is great! It's the first definition of exterior differentiation that ever really made sense to me. I think I'll be using this one from now on. | |
| Feb 19, 2011 at 19:00 | history | edited | Johannes Ebert | CC BY-SA 2.5 |
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| Feb 19, 2011 at 18:52 | history | answered | Johannes Ebert | CC BY-SA 2.5 |