Timeline for Coin flipping and a recurrence relation
Current License: CC BY-SA 2.5
19 events
when toggle format | what | by | license | comment | |
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Feb 20, 2011 at 17:30 | answer | added | Konstantinos Panagiotou | timeline score: 6 | |
Feb 18, 2011 at 14:47 | comment | added | Pradipta | That’s great to know, Mike. | |
Feb 17, 2011 at 23:21 | comment | added | Mike Spivey | @Pradipta: Thank you for asking this question! This question and the answers provided gave me the ideas I needed to answer one of my own MO questions from a while back: mathoverflow.net/questions/46777. | |
Feb 17, 2011 at 16:47 | vote | accept | Pradipta | ||
Feb 17, 2011 at 16:02 | comment | added | Pradipta | Yes, I tried that. Didn't get anywhere. | |
Feb 17, 2011 at 8:43 | comment | added | Gerhard Paseman | Looking at f(n+1) - f(n) gives 2^(-n-1) times sum of terms of the form (n choose k)(f(k+1) - f(k)), when n > 0. Have you investigated this path? Gerhard "Ask Me About System Design" Paseman, 2011.02.17 | |
Feb 17, 2011 at 0:56 | comment | added | Douglas Zare | The recurrence from mathoverflow.net/questions/11255/… is similar. That recurrence was the probability of a tie. | |
Feb 16, 2011 at 21:42 | answer | added | Mike Spivey | timeline score: 5 | |
Feb 16, 2011 at 16:30 | answer | added | Louigi Addario-Berry | timeline score: 7 | |
Feb 16, 2011 at 16:01 | answer | added | Or Zuk | timeline score: 3 | |
Feb 16, 2011 at 15:38 | answer | added | Did | timeline score: 11 | |
Feb 16, 2011 at 15:33 | comment | added | Pradipta | yeah. with probability $\frac{1}{2^n}$ no coin succeeds in round 1, thus you are back where you started. | |
Feb 16, 2011 at 15:30 | comment | added | Emil Jeřábek | Are you sure $f(n)$ appears on both sides of the first equation? | |
Feb 16, 2011 at 15:24 | comment | added | Pradipta | I think its working now. | |
Feb 16, 2011 at 15:20 | history | edited | Pradipta | CC BY-SA 2.5 |
broken formula fixed; added 2 characters in body
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Feb 16, 2011 at 15:20 | history | edited | Igor Rivin | CC BY-SA 2.5 |
changed the math, so it is slightly more readable, but still not great.
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Feb 16, 2011 at 15:18 | comment | added | Pradipta | something's wrong. I'll fix this. | |
Feb 16, 2011 at 15:17 | comment | added | Igor Rivin | I cannot parse the formula. | |
Feb 16, 2011 at 15:16 | history | asked | Pradipta | CC BY-SA 2.5 |