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Timeline for Superfluous definitions

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Feb 14, 2011 at 3:26 comment added ndkrempel @Harry: Thanks for making that clear.
Feb 14, 2011 at 0:16 comment added Harry Altman You have to be careful with how you define "inverse" here, though. You need a right identity $e$ and for each $a$ an $a^{-1}$ such that $aa^{-1}=e$ - note that here when we multiply by the inverse we get a specific right-identity. If we merely require for each $a$ there exists an $a^{-1}$ such that $aa^{-1}$ is some right-identity, it doesn't work.
Feb 13, 2011 at 23:28 history answered ndkrempel CC BY-SA 2.5