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Oct 11, 2014 at 23:14 answer added Hao Chen timeline score: 8
Aug 24, 2014 at 21:13 comment added Maarten Derickx See page 42 of math.harvard.edu/~elkies/modular.pdf
Aug 24, 2014 at 21:12 comment added Maarten Derickx I would say that this question would even be interesting in the rank 1 case. For example in the easiest rank one case $E=X_0^+(37)$ exactly $9$ of the points in $E(\mathbb Q)$ are heegner points and one point corresponds to the exceptional 37 isogeny. These 10 points are the only 10 with integer j-invariant. So for all the other $p \in E(\mathbb Q)$ the pullbacks to $X_0(37)$ will give quadratic numbers fields, but the curves over these points won't be CM. The points in $E(Q)$ whose lift is not CM might still be Heegner points though, since a Heegner point is a sum of CM points.
Feb 13, 2011 at 17:44 comment added Ramsey This reminds of a question that a friend and I tried to address some time ago. Namely, can one compute the polynomial $\prod(T-j(\alpha))$ where $\alpha$ varies over the fiber of such a modular parametrization. At the time, it seemed that computational resources weren't sufficient, but the situation may be different now. ...William?
Feb 13, 2011 at 12:20 answer added Chris Wuthrich timeline score: 5
Feb 13, 2011 at 10:03 history asked Kevin Buzzard CC BY-SA 2.5