Timeline for Codimension of Measurable Sets
Current License: CC BY-SA 2.5
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 13, 2011 at 18:15 | comment | added | Nick S | Fix a non-measurable set $A$. Then for any measurable set $B$, the set $A \Delta B$ is not measurable. This way you get a one-to-one function from the set of measurable sets to the set of non-measurable sets, which shows that there are at least as many non-measurables as measurables. | |
| Feb 13, 2011 at 18:13 | vote | accept | Jim Belk | ||
| Feb 13, 2011 at 13:31 | answer | added | Simon Thomas | timeline score: 13 | |
| Feb 13, 2011 at 13:22 | answer | added | Bill Johnson | timeline score: 8 | |
| Feb 13, 2011 at 10:38 | comment | added | Joel David Hamkins | I had posted an answer, but then realized it was flawed, so I deleted it. | |
| Feb 13, 2011 at 10:29 | comment | added | user5810 | I notice an answer just disappeared. (hopefully that wasn't a bug ...) | |
| Feb 13, 2011 at 8:20 | history | asked | Jim Belk | CC BY-SA 2.5 |