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Mar 11, 2014 at 11:26 comment added Johannes Hahn Why not use something like "A real X is a complex X together with a fixed choice of a complex conjugation such that the complex X is the complexification of the fixed points under conjugation"
Mar 11, 2014 at 10:40 answer added Rashidkhon timeline score: 0
Dec 16, 2011 at 18:43 answer added Mkouboi timeline score: 5
Dec 16, 2011 at 17:17 answer added Manny Reyes timeline score: 1
Dec 16, 2011 at 16:50 answer added Jon Bannon timeline score: 4
Feb 9, 2011 at 16:26 comment added Paul Siegel I just glanced back at the proof of the statement that a $\ast$-algebra of bounded operators on a complex Hilbert space is closed in the weak topology iff it is closed in the strong topology iff it is the same as its bicommutant, and I don't see any reason why the proof shouldn't work over a real Hilbert space, but I would be grateful to be corrected.
Feb 9, 2011 at 16:20 history asked Paul Siegel CC BY-SA 2.5