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Feb 4, 2011 at 5:00 comment added Martin Brandenburg Oh yes, sorry for my silly remark ...
Feb 4, 2011 at 0:20 history edited Tony Huynh CC BY-SA 2.5
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Feb 3, 2011 at 23:59 history edited Tony Huynh CC BY-SA 2.5
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Feb 3, 2011 at 10:45 comment added Tony Huynh @Martin: with $s=ck$, by (3) we have $ssss=ss$.
Feb 3, 2011 at 9:56 comment added Martin Brandenburg But the question asks for something like $kckckc = kckc$.
Feb 3, 2011 at 3:39 comment added Mariano Suárez-Álvarez You should really delete this answer: it ruins a celebrated general topology exercise! :)
Feb 3, 2011 at 3:37 history answered Tony Huynh CC BY-SA 2.5