Timeline for Reference request: representations of unipotent groups have a fixed point.
Current License: CC BY-SA 2.5
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 3, 2011 at 5:20 | comment | added | Keerthi Madapusi | A valid point. The fact is: I don't really know what definition I'm using! In the case I'm interested in, $U$ is the unipotent radical of a parabolic sub-group $P$ of a reductive group, and the fact I need is that $U$ acts trivially on every irreducible representation of $P$. | |
| Feb 3, 2011 at 5:06 | comment | added | mephisto | In asking a question like this, it would help to tell us what definition of a unipotent algebraic group (scheme) you are using. There are several different definitions in the literature, most of which are rather immediately equivalent to the existence of a nonzero fixed vector in any nonzero representation (this, in fact, works as a definition over any field). | |
| Feb 3, 2011 at 3:25 | answer | added | Richard Borcherds | timeline score: 5 | |
| Feb 3, 2011 at 3:22 | vote | accept | Keerthi Madapusi | ||
| Feb 3, 2011 at 3:16 | vote | accept | Keerthi Madapusi | ||
| Feb 3, 2011 at 3:16 | |||||
| Feb 3, 2011 at 3:08 | answer | added | Evan Jenkins | timeline score: 7 | |
| Feb 3, 2011 at 2:13 | history | asked | Keerthi Madapusi | CC BY-SA 2.5 |