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Jan 16, 2010 at 4:55 history edited user631 CC BY-SA 2.5
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Jan 14, 2010 at 7:05 comment added Pete L. Clark @FC: This is a great answer. But I think it's weird to refer to people whose work you are citing only by their initials, and weirder to insist on anonymity and also refer to your own work.
Nov 17, 2009 at 4:44 vote accept CommunityBot moved from User.Id=631 by developer User.Id=35318
Nov 17, 2009 at 3:43 history edited user631 CC BY-SA 2.5
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Nov 16, 2009 at 3:00 history edited user631 CC BY-SA 2.5
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Nov 15, 2009 at 22:18 history edited user631 CC BY-SA 2.5
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Nov 15, 2009 at 22:10 history edited user631 CC BY-SA 2.5
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Nov 15, 2009 at 12:18 comment added Kevin Buzzard p=257 is an interesting case, right? The class groups are Z/3 and Z/16, which are bad. Where are the reps coming from in that case?
Nov 15, 2009 at 11:20 comment added Kevin Buzzard For inspiration in the case $p=1$ mod $16$ one could take some 3-digit prime of this form, compute, and see why there are big dim spaces over $Q_2$. Are the associated mod 2 reps big (in the sense that they're giving reps to something bigger than $GL(2,Z/2Z)$? Or are the mod 2 reps small but the deformations are big? Did you try any computations FC? I looped over $p\leq 3700$ and found that the largest prime with all local pieces of size at most 5 was 257, by the way. So the conjecture that the local $d$ is growing looks plausible...
Nov 15, 2009 at 6:18 history edited user631 CC BY-SA 2.5
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Nov 15, 2009 at 6:05 history edited user631 CC BY-SA 2.5
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Nov 14, 2009 at 4:09 comment added JSE 1. Those Q-curves over Q(i) have bad reduction at 2 and p, not just p, if it matters to you. 2. I agree that it doesn't seem there'll be enough Q-curves. I wonder about RM abelian surfaces more generally. Is there a generally accepted heuristic, akin to "N^{5/6} elliptic curves of conductor at most N," for the number of RM abelian surfaces (say, with RM by a fixed real quadratic field K) of conductor at most N?
Nov 14, 2009 at 3:52 history edited user631 CC BY-SA 2.5
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Nov 13, 2009 at 18:20 history answered user631 CC BY-SA 2.5