Timeline for Independent Events Inducing Probability Measures
Current License: CC BY-SA 2.5
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 2, 2011 at 21:09 | history | edited | Alex R. | CC BY-SA 2.5 |
deleted 6 characters in body
|
| Feb 2, 2011 at 21:07 | comment | added | Alex R. | @Mark Meckes. Sorry I was using bad terminology. I just meant field | |
| Feb 2, 2011 at 20:14 | comment | added | Tom LaGatta | Alex R, note that such events $B$ need not exist. (cf. my question from a few days ago: mathoverflow.net/questions/54033/… ) | |
| Feb 2, 2011 at 19:51 | comment | added | Mark Meckes | "Sigma field" and "sigma algebra" mean the same thing. I guess from your response above that in that sentence you may have meant just "algebra". | |
| Feb 2, 2011 at 18:12 | history | edited | Alex R. | CC BY-SA 2.5 |
added 78 characters in body; added 3 characters in body
|
| Feb 2, 2011 at 18:00 | comment | added | Alex R. | @The Bridge: sorry for the confusion, corrected now | |
| Feb 2, 2011 at 14:27 | comment | added | Mark Meckes | In "Note that it's probably enough for $\mathcal{F}$ to be a sigma field" did you mean to say "ring"? | |
| Feb 2, 2011 at 9:08 | comment | added | The Bridge | Hi, I am not sure to fully understand your notation, does $\mathcal{C}$ depends only one the measure $P$ ?(so we can write it \mathcal{C}(P)) If this is the case, does $M(\mathcal{C})$ is the set of all measure $Q$ such that $\mathcal{C}(Q)=\mathcal{C}(P)$ ? Regards | |
| Feb 2, 2011 at 1:58 | history | edited | Alex R. | CC BY-SA 2.5 |
added 4 characters in body
|
| Feb 2, 2011 at 1:37 | history | asked | Alex R. | CC BY-SA 2.5 |