Timeline for An $L^0$ Khintchine inequality
Current License: CC BY-SA 4.0
16 events
when toggle format | what | by | license | comment | |
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S Apr 12 at 9:06 | history | suggested | The Amplitwist | CC BY-SA 4.0 |
fixed broken link to Wikipedia
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Apr 12 at 7:22 | review | Suggested edits | |||
S Apr 12 at 9:06 | |||||
Jul 15, 2020 at 12:37 | history | edited | George Lowther | CC BY-SA 4.0 |
deleted 16 characters in body
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Jul 10, 2020 at 8:41 | history | edited | George Lowther | CC BY-SA 4.0 |
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Jul 10, 2020 at 7:36 | history | edited | George Lowther | CC BY-SA 4.0 |
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Jul 10, 2020 at 7:29 | history | edited | George Lowther | CC BY-SA 4.0 |
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Jul 9, 2020 at 13:18 | history | edited | George Lowther | CC BY-SA 4.0 |
added 544 characters in body
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Nov 8, 2018 at 21:44 | answer | added | Ravi Boppana | timeline score: 10 | |
Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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Jun 3, 2015 at 19:58 | answer | added | Iosif Pinelis | timeline score: 13 | |
Jan 31, 2011 at 20:17 | history | edited | George Lowther | CC BY-SA 2.5 |
grammar. non-strict inequality
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Jan 31, 2011 at 12:52 | comment | added | George Lowther | Considering $a=(1,1,1,1,1,1)/\sqrt{6}$ gives a probability of $7/2^5=0.21875$. Wonder how close that is to optimal? | |
Jan 31, 2011 at 11:08 | comment | added | Shai Covo | ${\rm P}(|S| \geq 1) = 2[1-{\rm P}(S \lt 1)]$; ${\bf Problem 10} \star$ in math.leidenuniv.nl/~naw/home/ps/pdf/2008-2.pdf (perhaps open) asks for the probability ${\rm P}(S \lt 1)$. | |
Jan 31, 2011 at 10:07 | vote | accept | George Lowther | ||
Jan 31, 2011 at 8:46 | answer | added | Anthony Quas | timeline score: 24 | |
Jan 31, 2011 at 3:36 | history | asked | George Lowther | CC BY-SA 2.5 |