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Jun 24, 2011 at 8:22 history edited Tommaso Centeleghe CC BY-SA 3.0
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Jun 24, 2011 at 8:19 history undeleted Tommaso Centeleghe
Jun 24, 2011 at 8:18 history deleted Tommaso Centeleghe
May 11, 2011 at 15:21 comment added Tommaso Centeleghe Oh thanks! I did remember a group of ODD order was used in the solution. And yes, what I wrote above is non-sense...
May 10, 2011 at 22:59 comment added Frieder Ladisch Your group $G$ has $2^n$ elements and not $2n$, so this doesn't work. Usually this is done as follows: Take an abelian group $A$ of order $2n-1$ and identify $A$ with the matchdays. Choose a "jokerteam" and identify the other teams with $A$. Then on day $a\in A$, team $x$ is to play against team $a-x$, and team $2^{-1}a$ is to play against the jokerteam. At least, this system is used in the german Fußballbundesliga.
Jan 29, 2011 at 2:55 history answered Tommaso Centeleghe CC BY-SA 2.5