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Jan 27, 2011 at 17:22 comment added Dylan Thurston In this context, I guess it's better to talk about the cup product on cohomology than the intersection form, as the cup product is manifestly homotopy invariant.
Jan 27, 2011 at 14:56 comment added John Klein I realized I goofed on the dimension of my base space above. Thanks for the fix.
Jan 27, 2011 at 7:04 comment added Dylan Thurston Very nice, this is what I was looking for.
Jan 27, 2011 at 7:01 vote accept Dylan Thurston
Jan 26, 2011 at 22:45 comment added Allen Hatcher Another reason they have the same homotopy groups is that both fibrations have a section, so their long exact sequences of homotopy groups split.
Jan 26, 2011 at 21:52 history answered Somnath Basu CC BY-SA 2.5