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BrainDead
BrainDead
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Suppose that there isGiven a sequence $a_n$ such that $\sum_{n\ge1} \dfrac{|a_n|}{n^s}$ is convergent for $s>0$. Given that $\sum_{n\ge1} \frac{|a_n|}{n} < 1$, is it be possible to impose some sort of an upperbound for $\sum_{n\ge1} \frac{|a_n|}{n^s}$ for $1>s>k>0$ for some fixed $k$?

Suppose that there is a sequence $a_n$ such that $\sum_{n\ge1} \dfrac{|a_n|}{n^s}$ is convergent for $s>0$. Given that $\sum_{n\ge1} \frac{|a_n|}{n} < 1$, is it be possible to impose some sort of an upperbound for $\sum_{n\ge1} \frac{|a_n|}{n^s}$ for $1>s>k>0$ for some fixed $k$?

Given a sequence $a_n$ such that $\sum_{n\ge1} \dfrac{|a_n|}{n^s}$ is convergent for $s>0$. Given that $\sum_{n\ge1} \frac{|a_n|}{n} < 1$, is it be possible to impose some sort of an upperbound for $\sum_{n\ge1} \frac{|a_n|}{n^s}$ for $1>s>k>0$ for some fixed $k$?

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BrainDead
BrainDead
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Bounds on Riemann Zeta type Function?

Suppose that there is a sequence $a_n$ such that $\sum_{n\ge1} \dfrac{|a_n|}{n^s}$ is convergent for $s>0$. Given that $\sum_{n\ge1} \frac{|a_n|}{n} < 1$, is it be possible to impose some sort of an upperbound for $\sum_{n\ge1} \frac{|a_n|}{n^s}$ for $1>s>k>0$ for some fixed $k$?