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Jan 24, 2011 at 18:33 comment added darij grinberg Ah! (I know. Homological and -topical algebra seems to consist of definitions, theorems and abuses of notation.)
Jan 24, 2011 at 10:49 comment added Theo Buehler @darij: $C \otimes I$ is the mapping cylinder over the identity $C \to C$, see Weibel Ch. 1.6 for an explicit description of the complex. The notation $- \otimes I$ is a standard abuse from homotopical algebra.
Jan 24, 2011 at 9:10 comment added darij grinberg Also, it really doesn't work without countable sums? Can we prove it?
Jan 24, 2011 at 9:09 comment added darij grinberg What is $\otimes$ if the category is not moonoidal?
Jan 24, 2011 at 2:52 history edited John Klein CC BY-SA 2.5
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Jan 24, 2011 at 2:48 vote accept Eitan Chatav
Jan 24, 2011 at 2:39 comment added John Klein @Theo: Thanks for the reference and the observation.
Jan 24, 2011 at 2:30 comment added Theo Buehler But don't you assume that there are countable coproducts (or co-powers) in your argument? In that case it's a general fact about such pre-additive categories proved with essentially the same 'mapping telescope argument', see Freyd, Splitting homotopy idempotents, in: Proceedings of the Conference on Categorical Algebra, La Jolla, CA, 1965, Springer, New York, 1966, pp. 173–176.
Jan 24, 2011 at 2:15 comment added John Klein @Eitan: Good. Then my argument does apply.
Jan 24, 2011 at 2:03 comment added Eitan Chatav Yes, I mean that: the homotopy category of a category of chain complexes. In general I just want the underlying category to be Ab-enriched and idempotent-splitting. The categories I'm looking at are not monoidal though.
Jan 24, 2011 at 0:37 comment added John Klein Good point. Does Eitan's category have mapping cylinders and can one form colimits? I don't actually know what a "chain homotopy category" is. Maybe he means the homotopy category of a category of chain complexes. What are these complexes defined over?
Jan 24, 2011 at 0:15 comment added darij grinberg $\otimes$? $I$? What do we know about our category?
Jan 24, 2011 at 0:13 history answered John Klein CC BY-SA 2.5