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Jul 24, 2011 at 8:07 answer added user16007 timeline score: 2
Jan 27, 2011 at 16:26 vote accept Timothy Chow
Jan 22, 2011 at 10:30 answer added Charles Matthews timeline score: 9
Jan 22, 2011 at 9:03 answer added Pete L. Clark timeline score: 7
Jan 22, 2011 at 3:28 comment added Kevin O'Bryant I wouldn't expect exactly $\sqrt{p}$, and the expectation of the absolute value of the random walk isn't $\sqrt{p}$. The expectation of the square of a random walk (with $p$ unit steps) is $p$, but the square of the expectation is not the expectation of the square.
Jan 22, 2011 at 3:23 comment added Gerry Myerson Speaking solely for myself, what I would expect if I were to interpret the (quadratic) Gauss sum as a random walk is that most of the time its absolute value would be pretty close to $\sqrt p$; I would not expect it to be, as it is, exactly $\sqrt p$ all the time. Higher order Gauss sums are maybe closer to what I'd expect of a random walk (I'm not sure if that makes them better or worse candidates for the sort of application you have in mind).
Jan 22, 2011 at 0:54 history asked Timothy Chow CC BY-SA 2.5