Timeline for On base locus of canoncal linear system on surfaces
Current License: CC BY-SA 2.5
7 events
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Jan 23, 2011 at 17:14 | comment | added | rita | @Michael: that's right. | |
Jan 22, 2011 at 18:24 | comment | added | Tong | @rita: right. But I think using the technique of the proof of Noether inequality, maybe $M^2 \ge 2p_g-4$. | |
Jan 22, 2011 at 17:01 | comment | added | rita | If the canonical image of $S$ is a surface, then $M^2\ge p_g-1$. This improves the bound suggested by JC. | |
Jan 22, 2011 at 1:36 | comment | added | Tong | Yes, right. But as $p_g$ goes large, this bound seems not so beautiful. I do not know if there is a linear bound. | |
Jan 22, 2011 at 1:18 | comment | added | J.C. Ottem | Well, if $M^2>0$, the Hodge index theorem gives $$ K^2\le \frac{(K.M)^2}{M^2}\le (K.M)^2 $$ | |
Jan 21, 2011 at 23:37 | history | edited | Tong | CC BY-SA 2.5 |
added 44 characters in body
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Jan 21, 2011 at 23:26 | history | asked | Tong | CC BY-SA 2.5 |