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Apr 13, 2017 at 12:32 history edited CommunityBot
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Jan 21, 2011 at 17:19 comment added Suvrit Good point Igor; somehow I oversaw that in my haste. But I guess then one could argue that if even an inexact solution cannot be done better than in some time, say T, then getting an exact solution should be ever harder.
Jan 21, 2011 at 15:34 comment added Igor Rivin Notice that the OP specifically asks for "exact" solution.
Jan 20, 2011 at 14:30 comment added David Harris Gaussian Elimination over a black-box field $F$ requires $O(n^3)$ arithmetic operations, where an arithmetic operation is defined to be an access to the arithmetic oracle for $F$. In some fields, such as finite fields of fixed size, there is no coefficient growth so this estimate is exactly right. For fields such as $\mathbf R$ or $\mathbf C$, typically one approximates these with floating-point representations. In this case, Gauss Elimination uses $O(n^3)$ flops (but may commit some inaccuracy in the result).
Jan 20, 2011 at 9:48 history edited Suvrit CC BY-SA 2.5
added link to spielman
Jan 20, 2011 at 9:12 history answered Suvrit CC BY-SA 2.5