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Jan 21, 2011 at 18:08 comment added Tilman No - a nonlocal space may well have a local suspension spectrum. I can't think of a concrete example right now, but an $H\mathbb{Z}$-local space has to have a nilpotent fundamental group, which is something you can't see in the suspension spectrum. The other direction is more obviously false: $S^0$ (two points) is local for any theory, while the sphere spectrum isn't. For the different kinds of convergence questions, I'd like to point you to the excellent paper "conditionally convergent spectral sequences" by Mike Boardman.
Jan 21, 2011 at 7:41 vote accept Aaron Mazel-Gee
Jan 21, 2011 at 7:41 comment added Aaron Mazel-Gee Thanks a lot, this is very helpful. Two questions. A space is $E$-local iff its suspension spectrum is, right? Also, what do these terms strong/weak/conditional convergence mean?
Jan 19, 2011 at 15:05 comment added Tilman I meant infinite $X$ (fixed). Infinitely many cells.
Jan 19, 2011 at 15:04 history edited Tilman CC BY-SA 2.5
edited body
Jan 19, 2011 at 13:43 comment added Sean Tilson In your last sentence, what is meant by infinity $X$?
Jan 19, 2011 at 13:11 history edited Tyler Lawson CC BY-SA 2.5
backticks to the rescure
Jan 19, 2011 at 10:20 history answered Tilman CC BY-SA 2.5