While I'm not sure this question is appropriate for this site, here goes.

First, you need a maximal torus. Inside SO(5) we have SO(4) and then SO(2) x SO(2).

Write your antisymmetric matrices as

$$\begin{matrix} aJ & C & v \end{matrix} $$ $$\begin{matrix} -C^T & bJ & w \end{matrix} $$ $$\begin{matrix} -v^T & -w^T & 0 \end{matrix} $$ where $J = \left( {0\atop -1}{1\atop 0} \right) $, $C$ is square, and $v$ and $w$ are columns. Then the $a$ and $b$ parts are the torus, the $v$ gets you the $\pm x_1$ weights, the $w$ gets you the $\pm x_2$, and the $C$ gets you the $\pm x_1\pm x_2$.

Taking $x_1$ and $x_2 - x_1$ as simple roots, the $e_{x_1}$ is $$ 0 0 0 0 1 $$ $$ 0 0 0 0 i $$ $$ 0 0 0 0 0 $$ $$ 0 0 0 0 0 $$ $$ -1 -i 0 0 0 $$ and the $e_{x_2-x_1}$ is $$ 0 0 1 i 0 $$ $$ 0 0 i -1 0 $$ $$ -1 -i 0 0 0 $$ $$ -i 1 0 0 0 $$ $$ 0 0 0 0 0 $$ Sorry for the ugly matrices -- I'm having trouble getting the matrix environment working here.

While I'm not sure this question is appropriate for this site, here goes.

First, you need a maximal torus. Inside SO(5) we have SO(4) and then SO(2) x SO(2).

Write your antisymmetric matrices as

$$\begin{matrix} aJ & C & v \end{matrix} $$ $$\begin{matrix} -C^T & bJ & w \end{matrix} $$ $$\begin{matrix} -v^T & -w^T & 0 \end{matrix} $$ where $J = \left( {0\atop -1}{1\atop 0} \right) $, $C$ is square, and $v$ and $w$ are columns. Then the $a$ and $b$ parts are the torus, the $v$ gets you the $\pm x_1$ weights, the $w$ gets you the $\pm x_2$, and the $C$ gets you the $\pm x_1\pm x_2$.

Taking $x_1$ and $x_2 - x_1$ as simple roots, the $e_{x_1}$ is \begin{pmatrix} 0&0&0&0&1\\ 0&0&0&0&i\\ 0&0&0&0&0\\ 0&0&0&0&0\\ -1&-i&0&0&0 \end{pmatrix} and the $e_{x_2-x_1}$ is \begin{pmatrix} 0&0&1&i&0\\ 0&0&i&-1&0\\ -1&-i&0&0&0\\ -i&1&0&0&0\\ 0&0&0&0&0 \end{pmatrix}