Timeline for Does every polyomino tile R^n for some n?
Current License: CC BY-SA 2.5
5 events
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| Jan 20, 2011 at 8:56 | comment | added | domotorp | Oh, I forgot to put their complement, now I fixed it, thx. I was trying for a while but could not finish the proof from here, but it is a very interesting question. I think we can get all sorts of things that you write, but we will always have a little gap of the form (R\P)^k this way. | |
| Jan 20, 2011 at 8:53 | history | edited | domotorp | CC BY-SA 2.5 |
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| Jan 19, 2011 at 18:18 | comment | added | Dave Pritchard | Looks nice, but did you mean $R \times P \cup P \times R$ at the end? I wonder if it would be useful to push that idea further and get things like $R \times P \times P \cup P \times R \times P \cup P \times P \times R$ (maybe possible or not, maybe useful or not, I haven't thought yet) | |
| Jan 16, 2011 at 14:06 | history | edited | domotorp | CC BY-SA 2.5 |
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| Jan 16, 2011 at 10:37 | history | answered | domotorp | CC BY-SA 2.5 |