Timeline for Picard group of scheme over DVR
Current License: CC BY-SA 2.5
3 events
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Jan 18, 2011 at 15:21 | comment | added | Laurent Moret-Bailly | Shame on me. What was wrong in Matt's argument was the claim that the special fiber is irreducible, but as you show the conclusion nevertheless holds. What happens in my example is that if $L$ is an invertible sheaf on $X$, its restrictions to both components of $X_s$ must have the same degree. | |
Jan 16, 2011 at 3:28 | comment | added | Emerton | Dear Qing, This looks good to me. I guess I'll have to go back and reedit my answer! Best wishes, Matt | |
Jan 16, 2011 at 0:22 | history | answered | Qing Liu | CC BY-SA 2.5 |