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Timeline for Picard group of scheme over DVR

Current License: CC BY-SA 2.5

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Jan 18, 2011 at 15:21 comment added Laurent Moret-Bailly Shame on me. What was wrong in Matt's argument was the claim that the special fiber is irreducible, but as you show the conclusion nevertheless holds. What happens in my example is that if $L$ is an invertible sheaf on $X$, its restrictions to both components of $X_s$ must have the same degree.
Jan 16, 2011 at 3:28 comment added Emerton Dear Qing, This looks good to me. I guess I'll have to go back and reedit my answer! Best wishes, Matt
Jan 16, 2011 at 0:22 history answered Qing Liu CC BY-SA 2.5