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Jan 14, 2011 at 14:44 history edited J.C. Ottem CC BY-SA 2.5
added 222 characters in body; deleted 73 characters in body
Jan 14, 2011 at 14:43 comment added Francesco Polizzi Ah, this is interesting! In fact, by a result of Papantonopoulou, see jstor.org/stable/2042706, the normal bundle of a smooth subvariety $X$ in the Grassmannian $\mathbb{G}(1,3)$ is not ample if and only if $X$ is a Schubert cycle.
Jan 14, 2011 at 14:38 history edited J.C. Ottem CC BY-SA 2.5
added 18 characters in body
Jan 14, 2011 at 14:30 history answered J.C. Ottem CC BY-SA 2.5