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Jan 15, 2011 at 11:44 vote accept Jairo Bochi
Jan 17, 2011 at 6:12
Jan 15, 2011 at 9:59 history edited Francesco Polizzi CC BY-SA 2.5
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Jan 14, 2011 at 14:46 comment added Jairo Bochi Ok. I think I can reread this as follows (applying back the isomorphism): Take a splitting $\C^4 = E \oplus F$ where $\dim E = 1$, $\dim F = 3$. Take $Y$ (resp. $X$) as the set of $2$-spaces of $\C^4$ that contain $E$ (resp. are contained in $F$). Then $X$ and $Y$ are disjoint and $\dim X + \dim Y = 2 + 2 = \dim G(2,4)$. Thank you very much. Any idea about the second question?
Jan 14, 2011 at 14:36 comment added Francesco Polizzi Dear Allen, I think this is really a standard counterexample. I was just lucky to sit in front of my computer at the right moment :-)
Jan 14, 2011 at 14:32 comment added Allen Knutson Gah, too slow writing the same counterexample. Anyway the basic point is that the Betti numbers of projective space are all 1, but $b_4$ of G(2,4) is 2, with $\Sigma_p,\Sigma_H$ giving a basis.
Jan 14, 2011 at 14:28 history answered Francesco Polizzi CC BY-SA 2.5