Timeline for A good vector field to calculate the Euler's number of a compact differentiable manifold
Current License: CC BY-SA 2.5
7 events
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| Jan 13, 2011 at 20:12 | comment | added | algori | joaohelder -- any triangulation of the 2-sphere has 1-simplices, yet $H^1(S^2)=0$. In general there is no guarantee that a manifold $M$ admits a CW-structure such that the number of $q$-cells is the $q$-th Betti number. | |
| Jan 13, 2011 at 19:07 | comment | added | joaohelder | At least in well-behaved situations (as the above considered) this is the same. Correct? | |
| Jan 13, 2011 at 16:59 | answer | added | Johannes Ebert | timeline score: 3 | |
| Jan 13, 2011 at 16:37 | comment | added | algori | joaohelder -- do you want the number of zeroes to be equal the number of the $q$-simplices or the $q$-th Betti number? | |
| Jan 13, 2011 at 16:30 | history | edited | joaohelder | CC BY-SA 2.5 |
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| Jan 13, 2011 at 16:24 | history | edited | joaohelder | CC BY-SA 2.5 |
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| Jan 13, 2011 at 16:18 | history | asked | joaohelder | CC BY-SA 2.5 |