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Mar 24, 2011 at 4:02 comment added Olivier Bégassat can you make your statement more precise please? do you require p to be homogenuous? what is wrong with $p(x_1,\dots,x_d)=x_1^2+…+x_d^2−1$ and $M=\mathbb{S}^{d-1}$?
Jan 13, 2011 at 1:00 history answered Piazzon Federico CC BY-SA 2.5