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Jul 14, 2021 at 21:04 comment added Joseph Van Name Here is an example that has some interesting properties mathoverflow.net/a/396795/22277. Let $\rho_{f}$ denote the permutation matrix for permutation $f$. If $C_{n,r}$ is the $n\times n$-matrix where $C_{n,r}=(I_{n}+r\rho_{(r,r+1)})/(r+1)$, then $C_{n,1}\dots C_{n,n-1}$ is a doubly stochastic matrix with minimal polynomial $x^{n-1}(x-1)$ that is not diagonalizable.
S Jan 29, 2018 at 20:42 history suggested Rodrigo de Azevedo CC BY-SA 3.0
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Jan 29, 2018 at 20:22 review Suggested edits
S Jan 29, 2018 at 20:42
Jan 16, 2011 at 21:22 comment added Igor Rivin @Denis: let's be reductionist: A: does $x^2+1$ factor? B: over what field? Does this exchange make sense to you? If so, so should my previous comment.
Jan 13, 2011 at 20:19 history edited Kaveh Khodjasteh CC BY-SA 2.5
spellchecked the title!; added 2 characters in body
Jan 13, 2011 at 17:05 history edited Kaveh Khodjasteh CC BY-SA 2.5
changed title from diagonizable to non-diagonizable
Jan 13, 2011 at 16:56 vote accept Kaveh Khodjasteh
Jan 13, 2011 at 11:43 answer added Gerry Myerson timeline score: 9
Jan 13, 2011 at 9:09 comment added Denis Serre Igor, what do you think the field can be, if the entries are non-negative ?
Jan 13, 2011 at 8:05 answer added Denis Serre timeline score: 7
Jan 13, 2011 at 1:58 answer added David E Speyer timeline score: 33
Jan 13, 2011 at 0:26 comment added Igor Rivin Not diagonalizable over what field?
Jan 12, 2011 at 23:46 history asked Kaveh Khodjasteh CC BY-SA 2.5