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Jan 1, 2011 at 6:22 comment added Daniel Litt Hmm...if $0$ is not a natural number, then either $P$ or $Q$ contain $0$ and are not subsets of the natural numbers (as required by the question), or neither $P$ nor $Q$ contains zero, in which case $P+Q$ cannot contain $1$. So I think this just misses. But maybe it's late and I'm being stupid?
Dec 31, 2010 at 18:54 history edited Nikita Sidorov CC BY-SA 2.5
added 7 characters in body
Dec 31, 2010 at 18:24 history answered Nikita Sidorov CC BY-SA 2.5