Timeline for sign of special integral polynomials over roots of unity
Current License: CC BY-SA 2.5
6 events
when toggle format | what | by | license | comment | |
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Dec 31, 2010 at 9:56 | comment | added | Wadim Zudilin | Luis, you are kidding! There was already a post which has recognized 2 to be the oddest integer. :-) Too many constraints. Please try yourself to modify everything for $4\cdot3^2$. | |
Dec 31, 2010 at 7:54 | comment | added | Luis H Gallardo | $16 = 4 \cdot 2^2$ i.e., $h=2$ that is not odd | |
Dec 31, 2010 at 3:51 | comment | added | Wadim Zudilin | I finally realized that there was a pre-question to this question already answered by the (same) unknown. And I would join the above remark of the unknown: it is a strange question without sufficient motivation... | |
Dec 31, 2010 at 3:42 | history | edited | Wadim Zudilin | CC BY-SA 2.5 |
added context; Post Made Community Wiki
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Dec 31, 2010 at 2:38 | comment | added | Igor Rivin | I believe the question asks for $\pm 1$ coefficients, so this is not a counterexample. | |
Dec 31, 2010 at 2:28 | history | answered | Wadim Zudilin | CC BY-SA 2.5 |