Skip to main content
7 events
when toggle format what by license comment
Jul 30, 2016 at 23:34 comment added Peter May Ok, since I thought I had already answered this question, I've gone back and answered your other question mathoverflow.net/questions/245006/…. The negative homotopy groups of any suspension $G$-spectrum are zero. My long answer to mathoverflow.net/questions/65180/… is also relevant.
Jul 30, 2016 at 18:56 comment added Mikhail Bondarko Thank you! I am currently reading some texts on equivariant spectra including your book; yet this requires some time. As about formal properties: I am interested in an equivariant version of the vanishing of negative stable homotopy groups of spheres; cf. mathoverflow.net/questions/245006/…
Jul 30, 2016 at 18:00 comment added Peter May The proof is identical as for $G=e$, once you understand $G$-CW spectra, for which the source is math.uchicago.edu/~may/BOOKS/equi.pdf. The point is that they satisfy the same formal properties used in a standard proof for $G=e$. I can add full details, but I hope that is not necessary.
Jul 29, 2016 at 19:29 comment added Mikhail Bondarko Sorry, can you explan why the couple $(D^{\le 0}, D^{\ge 0})$ yields a t-structure? Surely, abstract nonsense yields the existence of a t-structure whose non-negative part is precisely $D^{\ge 0}$; should one apply some "standard topological argument" to compute $D^{\le 0}$ then?
Jan 4, 2011 at 22:28 vote accept user2146
Dec 29, 2010 at 16:43 history edited Charles Rezk CC BY-SA 2.5
escaped TeX
Dec 29, 2010 at 16:24 history answered Peter May CC BY-SA 2.5