Timeline for How to triangulate real projective spaces (as simplicial complexes in Mathematica)?
Current License: CC BY-SA 2.5
14 events
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Jul 7, 2023 at 22:29 | comment | added | მამუკა ჯიბლაძე | @MarianoSuárez-Álvarez But you still have hyperoctahedra in each dimension, right? They do give cell structures with $d+1$ vertices and $2^d$ highest dimensional cells, closure of each of the latter an embedded closed $d$-simplex (with all faces distinct) | |
Feb 8, 2011 at 5:08 | answer | added | Leo | timeline score: 2 | |
Dec 30, 2010 at 16:22 | vote | accept | Leo | ||
Dec 29, 2010 at 13:13 | answer | added | Leo | timeline score: 0 | |
Dec 26, 2010 at 3:31 | answer | added | John Palmieri | timeline score: 14 | |
Dec 26, 2010 at 2:41 | comment | added | Dev Sinha | John Palmieri at U Washington has recently implemented these same calculations in Sage. I suggest you send him an email. | |
Dec 26, 2010 at 1:11 | comment | added | Mariano Suárez-Álvarez | @Steven, regular polyhedra get scarce waaaaay too fast as the dimension grows :) | |
Dec 26, 2010 at 1:09 | answer | added | Mariano Suárez-Álvarez | timeline score: 5 | |
Dec 26, 2010 at 0:52 | comment | added | Steven Gubkin | RP^2 is obtained from the regular icosahedron by identifying opposite points. Have you tried looking at higher dimensional regular polyhedra? | |
Dec 25, 2010 at 23:47 | comment | added | j.c. | There are some interesting simplicial complexes on this page that you might play around with, though I don't see any with the topology of RP^3 infoshako.sk.tsukuba.ac.jp/~hachi/math/library/index_eng.html | |
Dec 25, 2010 at 23:37 | history | edited | Leo | CC BY-SA 2.5 |
added 27 characters in body
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Dec 25, 2010 at 23:31 | comment | added | Leo | Ball of dimension n. | |
Dec 25, 2010 at 23:27 | comment | added | user5810 | What are your $B^n$? | |
Dec 25, 2010 at 23:24 | history | asked | Leo | CC BY-SA 2.5 |