Timeline for Reachability for Markov process
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Feb 21, 2012 at 14:02 | history | edited | SBF | CC BY-SA 3.0 |
deleted 1 characters in body
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| Dec 23, 2010 at 13:58 | vote | accept | SBF | ||
| Dec 23, 2010 at 13:55 | comment | added | SBF | springerlink.com/content/0383j321m62n1u3t/fulltext.pdf Proposition 1 | |
| Dec 23, 2010 at 13:47 | comment | added | user6096 | @Gourtar: Could you provide a link or reference to the paper in question? | |
| Dec 23, 2010 at 13:41 | answer | added | user6096 | timeline score: 6 | |
| Dec 23, 2010 at 8:49 | comment | added | SBF | Haha, have you mentioned that the definition of $R(T,A)$ does not coincide with the definition of $I_A(X_\tau)$. Of course you can say it's obvious that if two triangles have the same sides, they are equal - but maybe you remember that this simple fact also need to be proved. | |
| Dec 22, 2010 at 19:21 | comment | added | Omer | That's an interesting way of phrasing this. Have you tried it for longer arguments? | |
| Dec 22, 2010 at 18:52 | comment | added | fedja | What particular phrase do you have difficulty with when translating back into the formal language? | |
| Dec 22, 2010 at 16:01 | comment | added | SBF | It's not a proof ) | |
| Dec 22, 2010 at 15:51 | comment | added | fedja | It says that if you blindfold someone moving at random and tell him when to stop and look, his chance to see a cow will be less than his chance to see it if he roams forever with open eyes but you can come close if you tell him to stop the first time you see a cow nearby or after a very long time whichever comes first. I doubt I can make it more obvious than that. The supremum can actually be taken over all stop-functions, but stopping times are enough to achieve it. As always, there are some measurability issues with continuous time, but, I guess, they are taken care of in the paper. | |
| Dec 22, 2010 at 14:01 | history | asked | SBF | CC BY-SA 2.5 |