Skip to main content
a minor typo
Source Link
Martin Sleziak
  • 4.7k
  • 4
  • 35
  • 40

Here is an elementary example from measure theory.

Usually Lp-spaces of a measurable space Z are defined with respect to some faithful measure μ on Z. More precisely, if p is a complex number with a nonnegative real part, then by definition Lp(Z,μ) consists of all functions f on Z such that μ(|f|1/ℜp) is finite if ℜp>0. If ℜp=0, then Lp(Z,μ) consists of all bounded functions on Z. (Here I use the algebraic convention for Lp-spaces, namely Lp=L1/p, in particular L0=L.)

Even though p is assumed to be complex, Lp(Z,μ) only depends on the real part of p. This will be fixed later.

It turns out that all spaces Lp(Z,μ) for different choices of a faithful measure μ are canonically isomorphic to each other. Suppose μ and ν are two faithful measures on Z and (Dμ:Dν) is the Radon-Nikodym derivative of μ with respect to ν, i.e., μ=(Dμ:Dν)ν. Then the map f∈Lp(Z,μ)⁠↦f(Dμ:Dν)p∈Lp(Z,ν) is an isomorphism. Observe that these isomorphisms are compatible with each other (i.e., passing from λ to μ and then from μ to ν is the same as passing from λ to ν and passing from μ to itself is identity). Hence we have a compatible system of isomorphisms as described in Marty's answer, therefore we can denote its limit (or colimit) by Lp(Z). Thus we no longer need to choose a measure to define Lp-spaces.

Individual spaces Lp(Z,μ) depend only on the real part of p, but the isomorphisms between them also depend on the imaginary part of p. Therefore, if p−q is imaginary, then Lp(Z) is isomorphic to Lq(Z) non-canonically. There is no canonical isomorphism because such a canonical isomorphism would give us a canonical measure on Z.

Thus we got rid of the dependence on the choice of a measure and obtained a meaningful definition of Lp-space for compexcomplex values of p.

The spaces L0(Z) and L1(Z) can be defined canonically without this procedure: L0(Z) is the space of all bounded functions on Z and L1(Z) is the space of all finite complex-valued measures on Z. However, all constructions of Lp(Z) for p∉⁠{0,1} known to me involve some kind of limit/colimit over all measures.

Here is an elementary example from measure theory.

Usually Lp-spaces of a measurable space Z are defined with respect to some faithful measure μ on Z. More precisely, if p is a complex number with a nonnegative real part, then by definition Lp(Z,μ) consists of all functions f on Z such that μ(|f|1/ℜp) is finite if ℜp>0. If ℜp=0, then Lp(Z,μ) consists of all bounded functions on Z. (Here I use the algebraic convention for Lp-spaces, namely Lp=L1/p, in particular L0=L.)

Even though p is assumed to be complex, Lp(Z,μ) only depends on the real part of p. This will be fixed later.

It turns out that all spaces Lp(Z,μ) for different choices of a faithful measure μ are canonically isomorphic to each other. Suppose μ and ν are two faithful measures on Z and (Dμ:Dν) is the Radon-Nikodym derivative of μ with respect to ν, i.e., μ=(Dμ:Dν)ν. Then the map f∈Lp(Z,μ)⁠↦f(Dμ:Dν)p∈Lp(Z,ν) is an isomorphism. Observe that these isomorphisms are compatible with each other (i.e., passing from λ to μ and then from μ to ν is the same as passing from λ to ν and passing from μ to itself is identity). Hence we have a compatible system of isomorphisms as described in Marty's answer, therefore we can denote its limit (or colimit) by Lp(Z). Thus we no longer need to choose a measure to define Lp-spaces.

Individual spaces Lp(Z,μ) depend only on the real part of p, but the isomorphisms between them also depend on the imaginary part of p. Therefore, if p−q is imaginary, then Lp(Z) is isomorphic to Lq(Z) non-canonically. There is no canonical isomorphism because such a canonical isomorphism would give us a canonical measure on Z.

Thus we got rid of the dependence on the choice of a measure and obtained a meaningful definition of Lp-space for compex values of p.

The spaces L0(Z) and L1(Z) can be defined canonically without this procedure: L0(Z) is the space of all bounded functions on Z and L1(Z) is the space of all finite complex-valued measures on Z. However, all constructions of Lp(Z) for p∉⁠{0,1} known to me involve some kind of limit/colimit over all measures.

Here is an elementary example from measure theory.

Usually Lp-spaces of a measurable space Z are defined with respect to some faithful measure μ on Z. More precisely, if p is a complex number with a nonnegative real part, then by definition Lp(Z,μ) consists of all functions f on Z such that μ(|f|1/ℜp) is finite if ℜp>0. If ℜp=0, then Lp(Z,μ) consists of all bounded functions on Z. (Here I use the algebraic convention for Lp-spaces, namely Lp=L1/p, in particular L0=L.)

Even though p is assumed to be complex, Lp(Z,μ) only depends on the real part of p. This will be fixed later.

It turns out that all spaces Lp(Z,μ) for different choices of a faithful measure μ are canonically isomorphic to each other. Suppose μ and ν are two faithful measures on Z and (Dμ:Dν) is the Radon-Nikodym derivative of μ with respect to ν, i.e., μ=(Dμ:Dν)ν. Then the map f∈Lp(Z,μ)⁠↦f(Dμ:Dν)p∈Lp(Z,ν) is an isomorphism. Observe that these isomorphisms are compatible with each other (i.e., passing from λ to μ and then from μ to ν is the same as passing from λ to ν and passing from μ to itself is identity). Hence we have a compatible system of isomorphisms as described in Marty's answer, therefore we can denote its limit (or colimit) by Lp(Z). Thus we no longer need to choose a measure to define Lp-spaces.

Individual spaces Lp(Z,μ) depend only on the real part of p, but the isomorphisms between them also depend on the imaginary part of p. Therefore, if p−q is imaginary, then Lp(Z) is isomorphic to Lq(Z) non-canonically. There is no canonical isomorphism because such a canonical isomorphism would give us a canonical measure on Z.

Thus we got rid of the dependence on the choice of a measure and obtained a meaningful definition of Lp-space for complex values of p.

The spaces L0(Z) and L1(Z) can be defined canonically without this procedure: L0(Z) is the space of all bounded functions on Z and L1(Z) is the space of all finite complex-valued measures on Z. However, all constructions of Lp(Z) for p∉⁠{0,1} known to me involve some kind of limit/colimit over all measures.

added 5 characters in body
Source Link
Dmitri Pavlov
  • 37.8k
  • 4
  • 97
  • 183

Here is an elementary example from measure theory.

Usually Lp-spaces of a measurable space Z are defined with respect to some faithful measure μ on Z. More precisely, if p is a complex number with a nonnegative real part, then by definition Lp(Z,μ) consists of all functions f on Z such that μ(|f|1/ℜp) is finite if ℜp>0. If ℜp=0, then Lp(Z,μ) consists of all bounded functions on Z. (Here I use the algebraic convention for Lp-spaces, namely Lp=L1/p, in particular L0=L.)

Even though p is assumed to be complex, Lp(Z,μ) only depends on the real part of p. This will be fixed later.

It turns out that all spaces Lp(Z,μ) for different choices of a faithful measure μ are canonically isomorphic to each other. Suppose μ and ν are two faithful measures on Z and (Dμ:Dν) is the Radon-Nikodym derivative of μ with respect to ν, i.e., μ=(Dμ:Dν)ν. Then the map f∈Lp(Z,μ)⁠↦f(Dμ:Dν)p∈Lp(Z,ν) is an isomorphism. Observe that these isomorphisms are compatible with each other (i.e., passing from λ to μ and then from μ to ν is the same as passing from λ to ν and passing from μ to itself is identity). Hence we have a compatible system of isomorphisms as described in Marty's answer, therefore we can denote its limit (or colimit) by Lp(Z). Thus we no longer need to choose a measure to define Lp-spaces.

Individual spaces Lp(Z,μ) depend only on the real part of p, but the isomorphisms between them also depend on the imaginary part of p. Therefore, if p−q is realimaginary, then Lp(Z) is isomorphic to Lq(Z) non-canonically. There is no canonical isomorphism because such a canonical isomorphism would give us a canonical measure on Z.

Thus we got rid of the dependence on the choice of a measure and obtained a meaningful definition of Lp-space for compex values of p.

The spaces L0(Z) and L1(Z) can be defined canonically without this procedure: L0(Z) is the space of all bounded functions on Z and L1(Z) is the space of all finite complex-valued measures on Z. However, all constructions of Lp(Z) for p∉⁠{0,1} known to me involve some kind of limit/colimit over all measures.

Here is an elementary example from measure theory.

Usually Lp-spaces of a measurable space Z are defined with respect to some faithful measure μ on Z. More precisely, if p is a complex number with a nonnegative real part, then by definition Lp(Z,μ) consists of all functions f on Z such that μ(|f|1/ℜp) is finite if ℜp>0. If ℜp=0, then Lp(Z,μ) consists of all bounded functions on Z. (Here I use the algebraic convention for Lp-spaces, namely Lp=L1/p, in particular L0=L.)

Even though p is assumed to be complex, Lp(Z,μ) only depends on the real part of p. This will be fixed later.

It turns out that all spaces Lp(Z,μ) for different choices of a faithful measure μ are canonically isomorphic to each other. Suppose μ and ν are two faithful measures on Z and (Dμ:Dν) is the Radon-Nikodym derivative of μ with respect to ν, i.e., μ=(Dμ:Dν)ν. Then the map f∈Lp(Z,μ)⁠↦f(Dμ:Dν)p∈Lp(Z,ν) is an isomorphism. Observe that these isomorphisms are compatible with each other (i.e., passing from λ to μ and then from μ to ν is the same as passing from λ to ν and passing from μ to itself is identity). Hence we have a compatible system of isomorphisms as described in Marty's answer, therefore we can denote its limit (or colimit) by Lp(Z). Thus we no longer need to choose a measure to define Lp-spaces.

Individual spaces Lp(Z,μ) depend only on the real part of p, but the isomorphisms between them also depend on the imaginary part of p. Therefore, if p−q is real, then Lp(Z) is isomorphic to Lq(Z) non-canonically. There is no canonical isomorphism because such a canonical isomorphism would give us a canonical measure on Z.

Thus we got rid of the dependence on the choice of a measure and obtained a meaningful definition of Lp-space for compex values of p.

The spaces L0(Z) and L1(Z) can be defined canonically without this procedure: L0(Z) is the space of all bounded functions on Z and L1(Z) is the space of all finite complex-valued measures on Z. However, all constructions of Lp(Z) for p∉⁠{0,1} known to me involve some kind of limit/colimit over all measures.

Here is an elementary example from measure theory.

Usually Lp-spaces of a measurable space Z are defined with respect to some faithful measure μ on Z. More precisely, if p is a complex number with a nonnegative real part, then by definition Lp(Z,μ) consists of all functions f on Z such that μ(|f|1/ℜp) is finite if ℜp>0. If ℜp=0, then Lp(Z,μ) consists of all bounded functions on Z. (Here I use the algebraic convention for Lp-spaces, namely Lp=L1/p, in particular L0=L.)

Even though p is assumed to be complex, Lp(Z,μ) only depends on the real part of p. This will be fixed later.

It turns out that all spaces Lp(Z,μ) for different choices of a faithful measure μ are canonically isomorphic to each other. Suppose μ and ν are two faithful measures on Z and (Dμ:Dν) is the Radon-Nikodym derivative of μ with respect to ν, i.e., μ=(Dμ:Dν)ν. Then the map f∈Lp(Z,μ)⁠↦f(Dμ:Dν)p∈Lp(Z,ν) is an isomorphism. Observe that these isomorphisms are compatible with each other (i.e., passing from λ to μ and then from μ to ν is the same as passing from λ to ν and passing from μ to itself is identity). Hence we have a compatible system of isomorphisms as described in Marty's answer, therefore we can denote its limit (or colimit) by Lp(Z). Thus we no longer need to choose a measure to define Lp-spaces.

Individual spaces Lp(Z,μ) depend only on the real part of p, but the isomorphisms between them also depend on the imaginary part of p. Therefore, if p−q is imaginary, then Lp(Z) is isomorphic to Lq(Z) non-canonically. There is no canonical isomorphism because such a canonical isomorphism would give us a canonical measure on Z.

Thus we got rid of the dependence on the choice of a measure and obtained a meaningful definition of Lp-space for compex values of p.

The spaces L0(Z) and L1(Z) can be defined canonically without this procedure: L0(Z) is the space of all bounded functions on Z and L1(Z) is the space of all finite complex-valued measures on Z. However, all constructions of Lp(Z) for p∉⁠{0,1} known to me involve some kind of limit/colimit over all measures.

replaced http://mathoverflow.net/ with https://mathoverflow.net/
Source Link

Here is an elementary example from measure theory.

Usually Lp-spaces of a measurable spacemeasurable space Z are defined with respect to some faithful measure μ on Z. More precisely, if p is a complex number with a nonnegative real part, then by definition Lp(Z,μ) consists of all functions f on Z such that μ(|f|1/ℜp) is finite if ℜp>0. If ℜp=0, then Lp(Z,μ) consists of all bounded functions on Z. (Here I use the algebraic convention for Lp-spaces, namely Lp=L1/p, in particular L0=L.)

Even though p is assumed to be complex, Lp(Z,μ) only depends on the real part of p. This will be fixed later.

It turns out that all spaces Lp(Z,μ) for different choices of a faithful measure μ are canonically isomorphic to each other. Suppose μ and ν are two faithful measures on Z and (Dμ:Dν) is the Radon-Nikodym derivative of μ with respect to ν, i.e., μ=(Dμ:Dν)ν. Then the map f∈Lp(Z,μ)⁠↦f(Dμ:Dν)p∈Lp(Z,ν) is an isomorphism. Observe that these isomorphisms are compatible with each other (i.e., passing from λ to μ and then from μ to ν is the same as passing from λ to ν and passing from μ to itself is identity). Hence we have a compatible system of isomorphisms as described in Marty's answer, therefore we can denote its limit (or colimit) by Lp(Z). Thus we no longer need to choose a measure to define Lp-spaces.

Individual spaces Lp(Z,μ) depend only on the real part of p, but the isomorphisms between them also depend on the imaginary part of p. Therefore, if p−q is real, then Lp(Z) is isomorphic to Lq(Z) non-canonically. There is no canonical isomorphism because such a canonical isomorphism would give us a canonical measure on Z.

Thus we got rid of the dependence on the choice of a measure and obtained a meaningful definition of Lp-space for compex values of p.

The spaces L0(Z) and L1(Z) can be defined canonically without this procedure: L0(Z) is the space of all bounded functions on Z and L1(Z) is the space of all finite complex-valued measures on Z. However, all constructions of Lp(Z) for p∉⁠{0,1} known to me involve some kind of limit/colimit over all measures.

Here is an elementary example from measure theory.

Usually Lp-spaces of a measurable space Z are defined with respect to some faithful measure μ on Z. More precisely, if p is a complex number with a nonnegative real part, then by definition Lp(Z,μ) consists of all functions f on Z such that μ(|f|1/ℜp) is finite if ℜp>0. If ℜp=0, then Lp(Z,μ) consists of all bounded functions on Z. (Here I use the algebraic convention for Lp-spaces, namely Lp=L1/p, in particular L0=L.)

Even though p is assumed to be complex, Lp(Z,μ) only depends on the real part of p. This will be fixed later.

It turns out that all spaces Lp(Z,μ) for different choices of a faithful measure μ are canonically isomorphic to each other. Suppose μ and ν are two faithful measures on Z and (Dμ:Dν) is the Radon-Nikodym derivative of μ with respect to ν, i.e., μ=(Dμ:Dν)ν. Then the map f∈Lp(Z,μ)⁠↦f(Dμ:Dν)p∈Lp(Z,ν) is an isomorphism. Observe that these isomorphisms are compatible with each other (i.e., passing from λ to μ and then from μ to ν is the same as passing from λ to ν and passing from μ to itself is identity). Hence we have a compatible system of isomorphisms as described in Marty's answer, therefore we can denote its limit (or colimit) by Lp(Z). Thus we no longer need to choose a measure to define Lp-spaces.

Individual spaces Lp(Z,μ) depend only on the real part of p, but the isomorphisms between them also depend on the imaginary part of p. Therefore, if p−q is real, then Lp(Z) is isomorphic to Lq(Z) non-canonically. There is no canonical isomorphism because such a canonical isomorphism would give us a canonical measure on Z.

Thus we got rid of the dependence on the choice of a measure and obtained a meaningful definition of Lp-space for compex values of p.

The spaces L0(Z) and L1(Z) can be defined canonically without this procedure: L0(Z) is the space of all bounded functions on Z and L1(Z) is the space of all finite complex-valued measures on Z. However, all constructions of Lp(Z) for p∉⁠{0,1} known to me involve some kind of limit/colimit over all measures.

Here is an elementary example from measure theory.

Usually Lp-spaces of a measurable space Z are defined with respect to some faithful measure μ on Z. More precisely, if p is a complex number with a nonnegative real part, then by definition Lp(Z,μ) consists of all functions f on Z such that μ(|f|1/ℜp) is finite if ℜp>0. If ℜp=0, then Lp(Z,μ) consists of all bounded functions on Z. (Here I use the algebraic convention for Lp-spaces, namely Lp=L1/p, in particular L0=L.)

Even though p is assumed to be complex, Lp(Z,μ) only depends on the real part of p. This will be fixed later.

It turns out that all spaces Lp(Z,μ) for different choices of a faithful measure μ are canonically isomorphic to each other. Suppose μ and ν are two faithful measures on Z and (Dμ:Dν) is the Radon-Nikodym derivative of μ with respect to ν, i.e., μ=(Dμ:Dν)ν. Then the map f∈Lp(Z,μ)⁠↦f(Dμ:Dν)p∈Lp(Z,ν) is an isomorphism. Observe that these isomorphisms are compatible with each other (i.e., passing from λ to μ and then from μ to ν is the same as passing from λ to ν and passing from μ to itself is identity). Hence we have a compatible system of isomorphisms as described in Marty's answer, therefore we can denote its limit (or colimit) by Lp(Z). Thus we no longer need to choose a measure to define Lp-spaces.

Individual spaces Lp(Z,μ) depend only on the real part of p, but the isomorphisms between them also depend on the imaginary part of p. Therefore, if p−q is real, then Lp(Z) is isomorphic to Lq(Z) non-canonically. There is no canonical isomorphism because such a canonical isomorphism would give us a canonical measure on Z.

Thus we got rid of the dependence on the choice of a measure and obtained a meaningful definition of Lp-space for compex values of p.

The spaces L0(Z) and L1(Z) can be defined canonically without this procedure: L0(Z) is the space of all bounded functions on Z and L1(Z) is the space of all finite complex-valued measures on Z. However, all constructions of Lp(Z) for p∉⁠{0,1} known to me involve some kind of limit/colimit over all measures.

Post Made Community Wiki
Source Link
Dmitri Pavlov
  • 37.8k
  • 4
  • 97
  • 183
Loading