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Sep 29, 2015 at 19:18 review Late answers
Sep 29, 2015 at 20:25
May 15, 2013 at 19:49 comment added Dag Oskar Madsen It would be nice if this thought experiment with two players with symmetrically opposite strategies could be turned into a simple explanation why the EV of the ratio $G/(B+G)$ \emph{cannot} be $1/2$. I don't quite see how to do it, but it seems only one player can gain money, and the loser will sit longer at the table than the winner does.
May 15, 2013 at 10:17 comment added user112109 @Steven Landsburg: DZ calculated the difference for 10 couples: 47.5 grils and 52.5 boys. Here comes my receipe for your gambling: Put everytime 1 million bucks on black. If black comes don't stand up but start your next series. During 10 series there will be less reds than blacks. It is really ridiculous that nobody ever thought about this simple method of making money! But what happens, if another player will bet on red everytime also always stopping a series, when red comes (not standing up then but starting the nexts series)? 52.5% red and simultaneously 52.5 % black? Overflow???
Dec 20, 2010 at 21:41 comment added Steven Landsburg I was with you right up "So the ratio remains equal". Your calculations are relevant to the difference, not to the ratio.
Dec 20, 2010 at 21:08 history answered Sandeep CC BY-SA 2.5