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Dec 20, 2010 at 3:49 comment added José Figueroa-O'Farrill Thanks for this. I think that my initial objection to your question was misguided and I've deleted my comment. Sorry about the noise! I now think that indeed what you wrote down is a Lie algebra. It's the Lie algebra obtained from the associative algebra in Scott's answer via the commutator.
Dec 20, 2010 at 1:26 comment added Jack Cheng Usually, I think $w_\infty$ is an Lie algebra, though it seems that $w_\infty$ can be viewed as an associative algebra. The algebra spanned by {$z^{\alpha_1}z^{\alpha_2}\partial_{z}^{\beta_1}\partial_{y}^{\beta_2}$} should be Lie algebra. "span" means as a linear basis.
Dec 19, 2010 at 15:34 comment added José Figueroa-O'Farrill I'm very confused by this question and this answer. In which sense is $w_\infty$ an algebra in this context? I have always understood it as a Lie algebra. It may simply come down to what "span" means in this context. Is it meant as a generating set? or as a linear basis? From your answer it seems you take it to mean the former. Is this standard?
Dec 19, 2010 at 12:25 vote accept Jack Cheng
Dec 19, 2010 at 8:43 history answered S. Carnahan CC BY-SA 2.5